Inside: where is it zero?
y = (x + 2)² is 0 when x = −2
y = x² is 0 when x = 0
So it moved 2 left: vector (−2, 0)
Maths · Higher · AQA · 45 minutes
Students predict which way a curve moves, then move it to find out why adding outside lifts it and adding inside slides it the opposite way. Slides to present, a vote that shows who's stuck, practice and homework.
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Predict first: when a goes up, which way will y = (x + a)² move? Then move a, and say why.
Lowest point: (−2, 0)
y = f(x) + a adds a to every y, so the curve moves up a. y = f(x + a) reaches each height when x is a less, so the curve moves left a: inside the bracket works the opposite way. y = −f(x) changes the sign of every y, a reflection in the x-axis; y = f(−x) changes the sign of every x, a reflection in the y-axis.
The lesson goes picture first. Students predict which way y = (x − 2)² moves before anyone explains, then move a outside and inside the bracket and say what happens, and why. Only then do they follow single points through each change and write equations from descriptions. It is Higher; the stretch combines two moves.
Students should substitute into function notation, such as f(3) for f(x) = x², and sketch y = x². Completing the square is needed for homework question 6.
Taught in Completing the square.
30 minutes in total. Each step says what changes for this length.
3 min 1 · Hook · students think
Students predict two moves before anyone explains.
For this length: Vote on (x − 2)² only; skip the second prediction
Say “y = x² becomes y = (x − 2)². Left or right, and by how much? And y = x² − 2? Write your predictions.”
Watch for Predicting left 2 for (x − 2)²: keep it. The next step is about exactly that.
Give a minute of silent writing, then vote: left or right? Many will say left, reading the minus as a direction.
Don't explain yet. The question is the point: one change goes the way it looks, the other the opposite way. Why?
Take a vote with Ask the class for (x − 2)²: left or right. A split class makes the next step matter.
Shorter: Vote on (x − 2)² only; skip the second prediction (−2 min).
8 min 2 · Explain · you explain
Move a outside, then inside the bracket; then the reflections; then one point through each.
For this length: Translations only; the reflections as a slide to read
Say “Outside the bracket changes y, the way it looks. Inside changes x, the opposite way.”
Watch for Moving f(x + a) right: the curve reaches each height at a smaller x, so it is a to the left.
Inside: where is it zero?
y = (x + 2)² is 0 when x = −2
y = x² is 0 when x = 0
So it moved 2 left: vector (−2, 0)
Reflect: f(x) = x² − 2x
−f(x) = −x² + 2x: in the x-axis
f(−x) = x² + 2x: in the y-axis
First slide: y = x² + a. Every y gets a added, so the curve moves up a: the vector (0, a). Move a; the reference curve y = x² stays.
Second slide: y = (x + a)². It is 0 when x = −a, where y = x² was 0 at x = 0: each point moves from x to x − a, so the curve moves left a, the vector (−a, 0). This answers the hook's vote.
Third slide: −f(x) changes the sign of every y, a reflection in the x-axis; f(−x) changes the sign of every x, a reflection in the y-axis. Then follow one point, (2, 4), through each change.
Vote before each move (Ask the class): a to 3 outside; a to 3 inside.
Shorter: Translations only; the reflections as a slide to read (−4 min).
5 min 3 · Your turn · students write
Each worked example beside a twin that students solve themselves.
For this length: Do the first two pairs only
Say “Watch me do one. Then you do its twin, which is almost the same.”
Watch for Changing both coordinates of a point when only one moves.
An equation from a move
y = x² moved 3 right
Inside, the opposite sign: y = (x − 3)²
Check: it is 0 at x = 3
Then theirs
y = x² moved 4 down
Follow a point
(1, 5) is on y = f(x)
y = f(x − 2): inside, x changes the opposite way
(1, 5) goes to (3, 5)
Then theirs
(1, 5) on y = f(x): where on y = f(x) − 2?
Two moves
y = x² reflected in the x-axis, then up 4
y = −x² + 4
It meets the x-axis at x = −2 and x = 2
Then theirs
y = x² moved 1 left, then 2 up
Work the first example aloud, writing each line. Then students solve its twin while you watch who changes the sign inside the bracket.
Do the same for each pair. The second pair catches students who change both coordinates.
Open the answers slide once most have finished their twins.
Shorter: Do the first two pairs only (−3 min).
9 min 4 · Who's stuck? · students vote
One question shows who's stuck; then practice in levels, and a stretch.
For this length: After the vote, questions 1–4 only
Say “Choose an answer on your own. Nobody talks until everyone has chosen.”
Watch for Moving the curve the way the sign looks.
Show your working: for each move, say whether x or y changes. The stretch is optional.
The question that shows who's stuck
Each wrong answer is a different mistake. While they answer, your Classroom shows who chose which, so you know in seconds whom to help with what.
Support · For question 3: f(x + 1) is inside the bracket, so only x changes, the opposite way to the sign. Which way, and how far?
Everyone chooses before anyone explains. If they moved it the way the sign looks, ask where (x − 4)² is zero. If they moved it up or down, ask whether the number is inside or outside the bracket.
Questions 1–2 build fluency; 3–4 change the look; 5–6 ask for reasons; 7 links to completing the square. The stretch combines two moves.
Students show their working on paper or the board; the quiz keeps their final answers.
If many moved it the way the sign looks, ask where (x − 4)² is 0 before they practise.
Shorter: After the vote, questions 1–4 only (−6 min).
Longer: The stretch, then: does the order of two moves matter? (+10 min).
5 min 5 · Exit · students show
One description and one point show who reads inside and outside correctly.
Say “Describe the move as a vector, and say where the lowest point goes.”
Watch for A vector with the wrong sign for the move inside the bracket.
A vector and one sentence are enough.
y = x² is moved to y = (x + 2)² − 1. Describe the move as a vector.
Then say where the lowest point goes, and why.
The answers show who still moves the curve the way the sign looks: start the next lesson with the hook's vote again. Set the homework.
Longer: Sketch both curves and label both lowest points (+5 min).
The answers, their slides and the mistake behind each wrong answer come with your copy. The worked examples above are open to everyone.
One-to-one: ask the student to predict each move aloud and say why, then check it by working out one point, such as where the lowest point goes.
For each move, say whether x or y changes, and which way. Give translations as vectors.
Print the worksheet with working space and homework. Teacher answers come with your Library copy.
Because the curve reaches each height when x is a smaller. y = (x + 2)² is 0 at x = −2, where y = x² was 0 at x = 0, so every point is 2 to the left. Inside the bracket changes x, the opposite way to the sign; outside changes y, the way it looks.
Ask what the minus changes. −f(x) is outside: every y turns round, a reflection in the x-axis. f(−x) is inside: every x turns round, a reflection in the y-axis. Follow one point, such as (2, 4), to check.
Higher. Students should know function notation and sketch y = x². The lesson uses y = x² and one other curve; completing the square helps with the questions that ask for a vector from an expanded quadratic.
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Curriculum reference: AQA GCSE Mathematics 8300: A13 (translations and reflections of a given function, Higher).
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