Start free

Quadratic inequalities Why is the answer to x² > 9 two inequalities, not just x > 3?

Higher · AQA · 45 minutes

Students find where a curve is above a line before anyone explains, then solve quadratic inequalities by sketching the curve through its roots and reading off where it is above or below the axis. Slides to present, a vote that shows who's stuck, practice and homework.

Present and print without signing in.

Use in my lessons

Free. The whole lesson is copied into your Library, yours to change.

For which x is the curve y = x² above the line y = k? Move k and write the answer for k = 1 and k = 4. What changes when k goes below 0?

−4−3−2−11234

They cross at (−2, 4) and (2, 4)

The idea in one minute

To solve a quadratic inequality, get 0 on one side and sketch the curve through its roots. Where the expression is more than 0, the curve is above the x-axis; where it is less than 0, below. For a curve with +x², below the axis is one piece between the roots, a < x < b, and above the axis is two pieces outside them, x < a or x > b: two inequalities, joined by or.

The lesson goes picture first. Students find where y = x² is above a line, and see the answer come in two pieces, so x > 2 alone can't be all of it. Then they factorise, as for a quadratic equation, sketch, and read off. Testing one number in each piece checks every answer. It is Higher; the stretch turns the curve upside down.

By the end, students can

  • explain why x² > 9 has two pieces to its answer
  • solve a quadratic inequality by sketching the curve through its roots
  • write the answer as one inequality or two, with < or ≤ as the question has it
  • check an answer by testing a number in each piece
  • count the integers that satisfy a quadratic inequality

Key words

  • quadratic inequality
  • roots
  • sketch
  • above the axis
  • below the axis
  • or

Before this lesson

Students should solve a quadratic by factorising (x² − 2x − 8 = 0), sketch y = x², and solve a linear inequality such as 2x + 1 < 7.

Taught in Quadratic equations.

The lesson, step by step

30 minutes in total. Each step says what changes for this length.

  1. 1 · Think3 min

    Where is the curve above?

    y = x² and the line y = k

    k = 4: for which x is x² > 4?

    Write every x you can find.

    Is x = −3 one of them?

    How many pieces is your answer?

    Write here

    3 min 1 · Hook · students think · the slides say “Think”

    Where is the curve above the line?

    Students find where y = x² is above a line before anyone explains.

    For this length: Ask about x = −3 at once; skip the silent minutes

    Say

    “Here are y = x² and the line y = 4. For which x is the curve above the line? Find as many as you can, then describe all of them.”

    Ask
    • Is x = −3 one of them? Is (−3)² more than 4?
    • How many pieces is your answer in?
    Watch for

    Writing x > 2 only: ask about x = −3, where x² is 9.

    For the teacher

    Give two minutes of silent work, then collect answers. Many will write x > 2, as if solving x² = 4.

    Don't explain yet. The question is the point: x = −3 works too, so what does the whole answer look like?

    Collect the answers as written. Keep x > 2 on its own on the board: the next step is about the piece it misses.

    Shorter: Ask about x = −3 at once; skip the silent minutes (−2 min).

  2. 2 · Watch8 min

    x² > 4: above the line

    x² = 4 at x = −2 and x = 2

    Above y = 4 outside them:

    x < −2 or x > 2

    Test x = −3: 9 > 4, true

    Shaded: the x that work. Dashed:

    −2 and 2 are not in.

    Two pieces: two inequalities.

    2 · Watch

    Below the axis: < 0

    x² − 2x − 8 < 0

    (x − 4)(x + 2) < 0

    Roots: x = −2 and x = 4

    Below the axis between them:

    −2 < x < 4

    Shaded: one piece, ends dashed

    One piece: one inequality.

    2 · Watch

    On or above the axis: ≥ 0

    x² + x − 6 ≥ 0

    (x + 3)(x − 2) ≥ 0

    On or above, outside the roots:

    x ≤ −3 or x ≥ 2

    ≤ and ≥: the roots are in,

    so the shading's edges are solid.

    Test x = 3: is 6 ≥ 0?

    2 · Watch

    One inequality or two?

    1. Get 0 on one side, with +x².

    2. Factorise: the roots are the ends.

    3. Sketch: < 0 is below the axis, > 0 above.

    Below, between the roots: a < x < b

    Above, outside them: x < a or x > b

    Never −2 > x > 2: no number is both.

    Check: test a number in each piece.

    8 min 2 · Explain · you explain · the slides say “Watch”

    Sketch, find the roots, read off

    Above or below the axis decides the answer; the roots are its ends; one inequality or two.

    For this length: Skip the ≥ slide; say that ≤ and ≥ include the roots

    Say

    “Get 0 on one side. Sketch the curve through its roots. More than 0 is where the curve is above the axis; less than 0 is where it is below.”

    Ask
    • x² − 2x − 8 < 0: where is the curve below the axis?
    • Can a number be less than −2 and more than 2 at once?
    Watch for

    Square-rooting as for an equation, and losing the negative piece.

    Above the line: x² > 4

    x² = 4 at x = −2 and x = 2

    y = x² is above y = 4 outside them

    x < −2 or x > 2

    Test x = −3: 9 > 4, true

    Below the axis: x² − 2x − 8 < 0

    (x − 4)(x + 2) < 0

    Roots: x = −2 and x = 4

    Below the axis between them: −2 < x < 4

    Test x = 0: −8 < 0, true

    On or above the axis: x² + x − 6 ≥ 0

    (x + 3)(x − 2) ≥ 0

    On or above the axis outside the roots

    x ≤ −3 or x ≥ 2

    For the teacher

    First slide: y = x² and the line y = 4 meet at x = −2 and x = 2. The curve is above the line on both outer sides: x < −2 or x > 2. Test x = −3: 9 > 4. So x > 2 alone misses half of the answer. The slide shades the x that work; its edges are dashed, as −2 and 2 are not in, just as for a region drawn with <.

    Second slide: get 0 on one side, then factorise, as for a quadratic equation. x² − 2x − 8 < 0 is (x − 4)(x + 2) < 0. The curve is below the axis between its roots: −2 < x < 4, one inequality.

    Third slide: ≥ 0 is on or above the axis: outside the roots, two pieces, x ≤ −3 or x ≥ 2. With ≤ and ≥ the roots are in, and the shading's edges are solid; with < and > they are not, and the edges are dashed.

    Fourth slide: one piece is one inequality, a < x < b; two pieces are two, joined by or. −2 > x > 2 would say x is below −2 and above 2 at once: no number is.

    Vote before each reading (Ask the class): one piece or two?

    Shorter: Skip the ≥ slide; say that ≤ and ≥ include the roots (−4 min).

  3. 3 · Your turn5 min

    Worked, then yours

    I do: x² < 16

    x² = 16 at x = −4 and x = 4

    Below y = 16 between them: −4 < x < 4

    You do: x² ≥ 25

    Sketch first: one piece or two?

    Write here

    3 · Your turn

    Two more pairs

    I do: x² − 5x + 6 > 0

    (x − 2)(x − 3) > 0: x < 2 or x > 3

    You do: x² + 2x − 15 ≤ 0

    I do: x² > 3x, so x² − 3x > 0

    x(x − 3) > 0: x < 0 or x > 3

    You do: x² ≤ 2x + 8

    Write here

    Its answers' slide comes with your copy.

    5 min 3 · Your turn · students write

    Worked, then yours

    Each worked example beside a twin that students solve themselves.

    For this length: Do the first two pairs only

    Say

    “Watch me do one. Then you do its twin, which is almost the same.”

    Ask
    • Above or below the axis? So one piece or two?
    Watch for

    Dividing x² > 3x by x to get x > 3: x could be negative, and the piece x < 0 is lost.

    Against a number

    x² < 16

    x² = 16 at x = −4 and x = 4

    Below y = 16 between them: −4 < x < 4

    Then theirs

    x² ≥ 25

    Factorise first

    x² − 5x + 6 > 0

    (x − 2)(x − 3) > 0

    Above the axis outside the roots: x < 2 or x > 3

    Then theirs

    x² + 2x − 15 ≤ 0

    Get 0 on one side

    x² > 3x, so x² − 3x > 0

    x(x − 3) > 0: roots 0 and 3

    Above the axis outside them: x < 0 or x > 3

    Then theirs

    x² ≤ 2x + 8

    For the teacher

    Work the first example aloud, writing each line and sketching the curve. Then students do its twin while you watch who writes one inequality for two pieces.

    Do the same for each pair. The third pair catches students who divide by x, or read off before getting 0 on one side.

    Open the answers slide once most have finished their twins.

    Shorter: Do the first two pairs only (−3 min).

  4. 4 · Vote and practise9 min

    Vote first

    Solve x² > 49.

    A: x < −7 or x > 7

    B: x > 7

    C: −7 < x < 7

    D: −7 > x > 7

    Choose on your own, then say why.

    4 · Vote and practise

    Practise: show your working

    1. x² < 36

    2. (x − 1)(x − 6) ≤ 0

    3. x² − 4x − 12 > 0

    4. x² ≥ 6x

    Stuck on 3? Factorise, sketch, then look.

    Write here

    4 · Vote and practise

    Reason it out

    5. x² < −4: which values of x?

    6. Is −1 > x > 1 right for x² − 1 > 0?

    7. How many integers make x² − 3x − 10 < 0?

    8. 2x² + 5x − 3 > 0

    Stretch: 6 + x − x² > 0. Which way up is the curve?

    9 min 4 · Who's stuck? · students vote · the slides say “Vote and practise”

    Vote, then practise

    One question shows who's stuck; then practice in levels, and a stretch.

    For this length: After the vote, questions 1–4 only

    Say

    “Choose an answer on your own. Nobody talks until everyone has chosen.”

    Ask
    • Test a number in each piece of your answer: does it work?
    Watch for

    Choosing without testing a number: ask for one number their answer includes, and check it.

    Sketch each curve through its roots and show your working on paper. Test a number in each piece. The stretch is optional.

    The question that shows who's stuck

    1. Solve x² > 49.
      1. x < −7 or x > 7
      2. x > 7
      3. −7 < x < 7
      4. −7 > x > 7
    In your Classroom, as they answer (an example)
    • A9
    • B11
    • C3
    • D4

    Each wrong answer is a different mistake. While they answer, your Classroom shows who chose which, so you know in seconds whom to help with what.

    1. x² < 36, so ___ < x < ___
    2. (x − 1)(x − 6) ≤ 0, so ___ ≤ x ≤ ___
    3. x² − 4x − 12 > 0, so x < ___ or x > ___
    4. x² ≥ 6x, so x ≤ ___ or x ≥ ___
    5. Which values of x satisfy x² < −4?
      1. None: x² is never negative
      2. −2 < x < 2
      3. x < −2 or x > 2
    6. Zara writes the answer to x² − 1 > 0 as −1 > x > 1. What is wrong?
      1. No number is below −1 and above 1 at once: write x < −1 or x > 1
      2. Nothing: it is right
      3. It should be −1 < x < 1
    7. How many integers satisfy x² − 3x − 10 < 0?
    8. 2x² + 5x − 3 > 0, so x < ___ or x > ___
    9. Stretch: 6 + x − x² > 0, so ___ < x < ___

    Support · For question 3: factorise x² − 4x − 12, sketch the curve through its roots, then ask where it is above the axis. How many pieces?

    For the teacher

    Everyone chooses before anyone explains. Then ask every student, whatever they chose: which of −10, 0 and 10 make x² > 49 true? Does your answer include exactly those? Name one number your answer includes.

    Questions 1–2 build fluency; 3–4 change the look; 5–6 ask for reasons; 7–8 are exam-style. The stretch turns the curve upside down.

    Students sketch and show their working on paper or the board; the quiz keeps their final answers.

    If the votes are split, test −10, 0 and 10 together in x² > 49, and sketch y = x² with the line y = 49, before they practise.

    Shorter: After the vote, questions 1–4 only (−6 min).

    Longer: The stretch, then: what changes when x² has a minus sign? (+10 min).

  5. 5 · Show what you know5 min

    Solve and sketch

    x² − x − 12 ≥ 0

    Sketch the curve through its roots.

    One inequality or two? Why?

    Then test a number in each piece.

    Write here

    5 min 5 · Exit · students show · the slides say “Show what you know”

    Solve one, say why

    One inequality solved and one sentence show who reads the sketch rather than a rule.

    Say

    “Solve it, sketch the curve, and say why your answer is one inequality or two.”

    Watch for

    Writing two pieces as one joined inequality.

    Show your working and your sketch; one sentence for the last part.

    1. Solve x² − x − 12 ≥ 0. Sketch the curve, and say in one sentence why your answer is one inequality or two.
    For the teacher

    Solve x² − x − 12 ≥ 0 and sketch the curve through its roots.

    Then say in one sentence why the answer is one inequality or two.

    The sentences show who reads the sketch: start the next lesson with the hook's curve and line if few do. Set the homework.

    Longer: Count the integers that do not satisfy it, and say why (+5 min).

One to one: ask the student to sketch before writing anything, then to test one number in each piece of their answer and one number outside it.

Homework: sketch and read off

Sketch each curve through its roots before you write the answer. Test one number in each piece of your answer.

  1. Solve x² ≤ 64.
  2. Solve x² − 7x + 10 < 0.
  3. Solve x² + 3x − 18 ≥ 0.
  4. Solve x² > 5x. Why must you not divide both sides by x?
  5. List every integer that satisfies x² − 2x − 15 < 0.
  6. Sketch y = x² + 4. Explain why every x satisfies x² + 4 > 0, and no x satisfies x² + 4 < 0.

Print the worksheet with working space and homework. Teacher answers come with your Library copy.

Teaching quadratic inequalities: common questions

Why is x² > 9 not just x > 3?

Because negative numbers square to positives: x = −5 gives 25, more than 9. On a graph, y = x² is above the line y = 9 on both outer sides, left of −3 and right of 3. Square-rooting as for an equation keeps one side only; a sketch shows both.

How do students know whether the answer is one inequality or two?

From the sketch, never a rule to learn. With +x², the curve is below the axis in one piece between the roots (a < x < b) and above it in two pieces outside them (x < a or x > b). With −x² it is the other way round, which is why the sketch is worth the ten seconds.

Should students sketch the curve or use a sign table?

Either gives the answer; the sketch shows why, and is quicker to check. This lesson sketches every time and tests one number in each piece. A sign table is a good second method for students going on to A level.

Is quadratic inequalities on the Foundation or Higher tier?

Higher. Students need to solve quadratic equations by factorising and solve linear inequalities first. The stretch, with −x², is the hardest case GCSE asks for.

Can I use the lesson without creating an account?

Yes. Read the lesson, print the worksheet and open its slides without signing in; nothing you draw there is kept. A free teacher account keeps the whole lesson in your Library to change and teach, with the quizzes, the answers and the answer slides.

Curriculum reference: AQA GCSE Mathematics 8300: A22 (quadratic inequalities in one variable, Higher), with A11 (roots from a graph) and A18 (solving quadratics by factorising).

Teach this lesson tomorrow

Keep the whole lesson, change what you like, and use it with a group. Present its slides step by step while each student works on their own copy.

Use in my lessons

Free. The whole lesson is copied into your Library, yours to change.

In our own words; free to use with your students. Not endorsed by any exam board.