Complete the square
x² − 4x + 1
Half of −4 is −2: (x − 2)² = x² − 4x + 4
x² − 4x + 1 = (x − 2)² − 3
Lowest point: (2, −3)
Maths · Higher · AQA · 45 minutes
Students find the lowest point of a curve, then see why y = (x − p)² + q has it at (p, q), and complete the square to find it and to solve. Slides to present, a vote that shows who's stuck, practice and homework.
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Before you move p, say where the lowest point will go. Why is its height always 1?
Lowest point: (2, 1)
A square is never negative, so (x − p)² + q is smallest when x = p, and then y = q: the curve's lowest point, its turning point, is (p, q). Completing the square writes x² + bx + c in that form: halve b and write (x + b ÷ 2)², then take away (b ÷ 2)² to keep it equal. The lowest point is at x = −b ÷ 2.
The lesson goes picture first. Students find the lowest point on a graph before anyone explains, then move p and q and say where it goes. Only then do they complete the square, read off the turning point, and solve equations that don't factorise. It follows the lesson on solving quadratics by factorising; the stretch has a number in front of x².
Students should expand (x + 3)² and solve quadratics by factorising. Square roots and surds such as √3 are used; completing the square is taught here.
Taught in Quadratic equations.
60 minutes in total. Each step says what changes for this length.
5 min 1 · Hook · students think
Students find a curve's lowest point before anyone explains.
Say “Here is y = x² − 4x + 5. Find its lowest point from the graph. Then: where in the equation could you see it?”
Watch for Answering with the y-intercept, (0, 5): ask whether the curve goes lower.
Give two minutes of silent work. Most read (2, 1) off the graph; some notice the curve is the same height either side of x = 2.
Don't explain yet. The question is the point: the equation doesn't show 2 or 1. Could another way of writing it?
Gather guesses with Ask the class. Keep (2, 1) for the next step, and anyone who tried a square.
Shorter: Show the curve and its lowest point; skip the guessing round (−2 min).
12 min 2 · Explain · you explain
Move p and q; then write x² − 4x + 1 as (x − 2)² − 3 and solve with it.
Say “A square is never negative. So when is (x − 2)² + 1 smallest?”
Watch for Adding the square of half of b instead of taking it away.
Complete the square
x² − 4x + 1
Half of −4 is −2: (x − 2)² = x² − 4x + 4
x² − 4x + 1 = (x − 2)² − 3
Lowest point: (2, −3)
Solve with it
x² − 4x + 1 = 0
(x − 2)² = 3
x − 2 = √3 or −√3
x = 2 + √3 or x = 2 − √3
First slide: y = (x − p)² + q. The square is never negative and is 0 at x = p, so the lowest y is q, at x = p. Move p: the curve slides sideways. Move q: it slides up and down. The lowest point is always (p, q).
Second slide: x² − 4x + 1. Halve −4 to get −2. (x − 2)² = x² − 4x + 4, which is 3 too many, so x² − 4x + 1 = (x − 2)² − 3, lowest point (2, −3). Expand it back to check.
Third slide: to solve x² − 4x + 1 = 0, (x − 2)² = 3, so x − 2 = ±√3. The curve shows both solutions, either side of x = 2.
Vote before each move (Ask the class): p to −1, then q to −2.
Shorter: Move p only; one worked example (−4 min).
8 min 3 · Your turn · students write
Each worked example beside a twin that students solve themselves.
Say “Watch me do one. Then you do its twin, which is almost the same.”
Watch for Halving b but not squaring it.
The turning point
x² + 6x + 4
(x + 3)² = x² + 6x + 9
x² + 6x + 4 = (x + 3)² − 5
Lowest point: (−3, −5)
Then theirs
x² + 8x + 10
Real roots or not?
x² − 2x + 5 = (x − 1)² + 4
(x − 1)² + 4 is at least 4
So x² − 2x + 5 = 0 has no real roots
Then theirs
x² − 6x + 11 = 0
Solve exactly
x² + 4x − 1 = 0
(x + 2)² − 5 = 0, so (x + 2)² = 5
x = −2 + √5 or x = −2 − √5
Then theirs
x² − 6x + 4 = 0
Work the first example aloud, writing each line, and expand the square back out to check. Then students do its twin.
Do the same for each pair. The second pair links back to no real roots; the third catches students who take only the positive root.
Open the answers slide once most have finished their twins.
Shorter: Do the first and third pairs only (−3 min).
25 min 4 · Who's stuck? · students vote
One question shows who's stuck; then practice in levels, and a stretch.
For this length: The stretch, then: why does a 2 in front of x² change the method?
Say “Choose an answer on your own. Nobody talks until everyone has chosen.”
Watch for Adding the square instead of taking it away.
Show your working, and expand your square back out to check it. The stretch is optional.
The question that shows who's stuck
Each wrong answer is a different mistake. While they answer, your Classroom shows who chose which, so you know in seconds whom to help with what.
Support · For question 1: half of 10 is 5, so start with (x + 5)². It expands to x² + 10x + 25. You only want + 7: what must you take away?
Everyone chooses before anyone explains. If they added the square, ask them to expand their answer back out. If they halved without squaring, ask what (x − 3)² expands to.
Questions 1–2 build fluency; 3–4 change the look; 5–6 ask for reasons; 7 works backwards. The stretch has 2x².
Students show their working on paper or the board; the quiz keeps their final answers.
If many added the square, or took away half of b without squaring it, expand (x − 3)² together before they practise.
Shorter: After the vote, questions 1–4 only (−6 min).
Longer: The stretch, then: why does a 2 in front of x² change the method? (+10 min).
10 min 5 · Exit · students show
One square completed and one reason show who links (p, q) to the roots.
For this length: Sketch it, marking the lowest point and the y-intercept
Say “Complete the square, then decide whether the curve meets the x-axis. Say how you know.”
Watch for Deciding from the sign of the number at the end of x² − 10x + 30, not from q.
Show your working; one sentence for the reason.
Write x² − 10x + 30 in the form (x − p)² + q.
Then answer the exit question: does y = x² − 10x + 30 meet the x-axis?
The reasons show who uses the lowest point to decide: start the next lesson with one that didn't. Set the homework.
Longer: Sketch it, marking the lowest point and the y-intercept (+5 min).
The answers, their slides and the mistake behind each wrong answer come with your copy. The worked examples above are open to everyone.
One-to-one: ask the student to expand their square back out every time, to check it gives the expression they started with.
Show each square completed, and expand it back out to check. Give exact answers with surds for question 5.
Print the worksheet with working space and homework. Teacher answers come with your Library copy.
Start with the picture: y = (x − p)² + q has its lowest point at (p, q), because a square is never negative and is 0 at x = p. Completing the square rewrites x² + bx + c in that form: halve b, write the square, then take away the extra number the square brings, so the two stay equal.
Write the quadratic as (x − p)² + q. The square is 0 when x = p, so the turning point is (p, q). For x² + 6x + 4 = (x + 3)² − 5, p = −3 and q = −5, so it is (−3, −5). Expand the square back out to check.
Higher. This lesson follows solving quadratics by factorising: students should be able to expand (x + 3)² and factorise first. The stretch, with 2x², goes a step further.
Yes. Read the lesson, print the worksheet and open its slides without signing in; nothing you draw there is kept. A free teacher account keeps the whole lesson in your Library to change and teach, with the quizzes, the answers and the answer slides.
Curriculum reference: AQA GCSE Mathematics 8300: A11 (turning points by completing the square) and A18 (solving quadratics by completing the square), Higher.
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